Sorry, there’s mistakes in the code, i just translated the names in english before posting it , and moreover there’s no indentation

But, it’s now posted on my wiki : http://www.wumzi.info/wiki/doku.php?id=decodeur_de_code_cesar

Yes, I’m from France

@Ulrik: Cheers for the link, that looks like a simpler solution however I don’t think it could be used for the customizations that I’d like to include in future versions (such as methods for defeating frequency analysis)

See http://stackoverflow.com/questions/1538935/caesars-cipher-using-python-could-use-a-little-help/1539611#1539611

Instead of a dictionnary, you could have used a string in order to run the string.translate() method instead of lines 13-17.

I made a caesar decoder, which use a dictionnary of words to decode :

#!/usr/bin/env python
import string

def decode (n, text):

#First, we build the coded-alphabet for n substitutions
alphabet= ‘abcdefghijklmnopqrstuvwzyz’
alphabet_code = ””
for x in range (0, len(alphabet)):
d = 0
for y in range (0, n+1):
if x+y -d > 25:
x=0
d = y
letter=alphabet[x +y -d]
y += 1
alphabet_code += letter
x += 1

table = string.maketrans(alphbet_code , alphabet) #Decoding

#Then, by checking every decoded word with a dictionnary, we check if the decoded string is the right
decode=text.translate(table)
file=open(‘dictionnary.txt’ , ‘r’)
words= file.readlines()
good=0
for x in words:
if x[0:-1] in decode and len(x) > 3:
good += 1
if bon > 1:
print decode
file.close()

if __name__ == ‘__main__’:
text = raw_input(‘Enter the Caesar message to decode’).lower()
for z in range (1, 27):
decode ( z , text)
z += 1